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Re: Float procedure [message #13747 is a reply to message #13742]

Wed, 02 December 1998 00:00

Alex Schuster
Messages: 124
Registered: February 1997

Senior Member

Charlie Solomon wrote:

> Can anyone shed some light on how this byte array is converted into a
> floating point number?
> two_words = bytarr(4)
> two_words = [244, 232, 165, 64]

Caution! This statements creates an intarr(4). You could define
two_words this way:

IDL> two_words = [244b, 232b, 165b, 64b]

> IDL> print, float(two_words, 0)
> 2.13062e-038

I get this result:

IDL> f = float( two_words, 0 )
IDL> print, f
-1.47457e+32

This still isn't the value you expect, because your PC uses another byte
ordering scheme than my workstation. Changing this with the swap_endian
routine corrects this:

IDL> print, swap_endian( f )
5.18469

Alex
--
Alex Schuster Wonko@weird.cologne.de PGP Key available
alex@pet.mpin-koeln.mpg.de

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[Message index]

		Re: Float procedure By: eddie haskell on Wed, 02 December 1998 00:00
		Re: Float procedure By: Liam Gumley on Wed, 02 December 1998 00:00
		Re: Float procedure By: Alex Schuster on Wed, 02 December 1998 00:00

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