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Re: DAY OF YEAR [message #17461 is a reply to message #17459]

Mon, 25 October 1999 00:00

Ben Tupper
Messages: 186
Registered: August 1999

Senior Member

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Howdy,
Haje Korth wrote:
<blockquote TYPE=CITE>Hi folks,
 Sometimes RSI is driving me nuts with introducing new stuff and making
 old stuff obsolete.
 Can anybody tell me with their new date/time format code, how to print
 the day of the year (doy). It should be something like:
 a=julday(month,day,year,hour,min,sec)
 print,a,format='(c(???????))'
  </blockquote>
You could calculate the DOY with the following.
IDL> Today = JulDay(10,26,1999)
 IDL> BenchMark = JulDay(1,1,1999)
 IDL> print,Today-BenchMark
           298
Note that this DOY implies that Jan 1 is D0Y 0... which is ok for somefolks
but not others.   I can't think of the need for it, but sometimes
the first DOY is considered DOY 1.    (Just when I was getting
used to counting from Zero and having only nine fingers!)
  
<pre>-- 
Ben Tupper

Bigelow Laboratory for Ocean Science
tupper@seadas.bigelow.org

Pemaquid River Company
pemaquidriver@tidewater.net</pre>
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[Message index]

		Re: DAY OF YEAR By: Ben Tupper on Tue, 26 October 1999 00:00
		Re: DAY OF YEAR By: thompson on Mon, 25 October 1999 00:00
		Re: DAY OF YEAR By: Ben Tupper on Mon, 25 October 1999 00:00

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