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Re: Given many images, find bounding box [message #17821 is a reply to message #17632]

Fri, 05 November 1999 00:00

hhpt
Messages: 3
Registered: August 1999

Junior Member

Hi Dick,

Well, this is not correct, for example, if I havbe only one patch,
the upper left hand corner has the coordinate (1,10) (lon, lat) and the
box has lon_size = 6 and lat_size = 8

then the expected answer should be:
left = 1
right 7
top = 10
bottom = 2
but using your formular the answers would be:
left = 1
right 6
top = 10
bottom = 3

Also, it will be nice some how if it could take care of the +/- degrees
too...... seems tricky....

-- Herbert

> This is pretty straightforward, but I have to make a few assumptions:
>
> - you have four arrays (lat, lon, rows, cols) containing values
> for each of your patches
> - all four are measured in pixels
> - 'lat' increases as you go up, 'lon' increases as you go to the right
> (no wrapping at lat +/- 90 or lon +/- 180 here, do you need that?
> My, that would be interesting...)
> - you want the *smallest* bounding box that contains the patches
>
> Then the four edges of that bounding box are:
>
> left = Min(lon)
> top = Max(lat)
> right = Max(lon + cols - 1)
> bottom = Min(lat - rows + 1)
>
> Hope this helps!
>
> Cheers,
> -Dick
>
> Dick Jackson Fanning Software Consulting, Canadian Office
> djackson@dfanning.com Calgary, Alberta Voice/Fax: (403) 242-7398
> Coyote's Guide to IDL Programming: http://www.dfanning.com/
>
>

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[Message index]

		Re: Given many images, find bounding box By: Dick Jackson on Fri, 05 November 1999 00:00
		Re: Given many images, find bounding box By: Dick Jackson on Mon, 08 November 1999 00:00
		Re: Given many images, find bounding box By: Dick Jackson on Sat, 06 November 1999 00:00
		Re: Given many images, find bounding box By: hhpt on Fri, 05 November 1999 00:00

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