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Re: How to convert (concatenate) a string array to a string scalar? [message #19415 is a reply to message #19283] Tue, 14 March 2000 00:00 Go to previous messageGo to previous message
John-David T. Smith is currently offline  John-David T. Smith
Messages: 384
Registered: January 2000
Senior Member
Mike Fitzgibbon wrote:
>
> In article <38CD6DA1.6E45DF18@astro.cornell.edu>,
> J.D. Smith <jdsmith@astro.cornell.edu> wrote:
>> David Fanning wrote:
>>>
>>> Alex Schuster (alex@pet.mpin-koeln.mpg.de) writes:
>>>
>>>> BEEEEEP! There's no need for that, here's a function which does what
>>>> Kristian wants:
>>>>
>>>> function strconcat, numarray
>>>> format = string( '(', n_elements( numarray ), '(I0,', '","))' )
>>>> str = string( numarray, format=format )
>>>> return, strmid( str, 0, strlen( str ) - 1 )
>>>> end
>>>>
>>>> In the example above, the format string which is created inside the
>>>> function would be '3(I0,",")' , which tells the STRING routine to take
>>>> three integers and add them to the string without leading blanks, but
>>>> with a comma between them. The last strmid call only removes the last
>>>> comma from the string.
>>>
>>> I only know one thing for certain about IDL, and that
>>> is this:
>>>
>>> There is an inverse correlation between how certain
>>> I am that something can only be done one way in IDL
>>> and the number of alternative methods I will learn
>>> about in the next 15 minutes.
>>>
>>> :-(
>>
>> Obfuscated IDL Contest Entry:
>>
>> s=string((reform((tmp=byte(strtrim(a,2)+[replicate(",",n_elements(a)-1), ""])),$
>> n_elements(tmp)))[where(tmp ne 0)])

> Why not just use the format termination code:
>
> s = string(a,format='('+strtrim(n_elements(a))+'(I0,:,","))')
>
> (Coincidentally, I happened to need to do this this morning)

Because it's not nearly obfuscated enough. And Alex already did that one.

JD

--
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Cornell University Dept. of Astronomy |*| (607) 255-6263
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