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Re: unwrap modulo 2pi [message #23637 is a reply to message #23636]

Wed, 07 February 2001 11:48

Randall Skelton
Messages: 169
Registered: October 2000

Senior Member

Modulo Operator Notes

quotient: q = a / b
remainder: r = a mod b

So,

a b a/b a mod b
10 3 3 1
3 10 0 3
-10 -3 -3 -1

It is *always* true that a = q*b + r with abs(r) < abs(b) and b neq 0

Randall

graham_wilson@my-deja.com wrote:
> My appologies for not being explicit enough...
>
> IDL> a=[2,4,6,8,10,12]
> IDL> a=[2.,4.,6.,8.,10.,12.]
> IDL> b=2*!PI
> IDL> c=a mod b
> IDL> print, c
> 2.00000 4.00000 6.00000 1.71681 3.71681 5.71681
>
> What I mean by 'unwraping' is: Given I know 'c' and 'b' how do I
> explicitly find a?
>

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[Message index]

		Re: unwrap modulo 2pi By: Pavel A. Romashkin on Wed, 07 February 2001 15:25
		Re: unwrap modulo 2pi By: Craig Markwardt on Wed, 07 February 2001 13:07
		Re: unwrap modulo 2pi By: Pavel A. Romashkin on Wed, 07 February 2001 12:39
		Re: unwrap modulo 2pi By: Randall Skelton on Wed, 07 February 2001 11:48
		Re: unwrap modulo 2pi By: tam on Wed, 07 February 2001 11:18
		Re: unwrap modulo 2pi By: Dave Greenwood on Wed, 07 February 2001 10:48
		Re: unwrap modulo 2pi By: Dave Greenwood on Wed, 07 February 2001 10:29
		Re: unwrap modulo 2pi By: graham_wilson on Wed, 07 February 2001 09:52
		Re: unwrap modulo 2pi By: Pavel A. Romashkin on Wed, 07 February 2001 09:02
		Re: unwrap modulo 2pi By: graham_wilson on Wed, 07 February 2001 07:30
		Re: unwrap modulo 2pi By: Wim Bouwman on Fri, 09 February 2001 00:42
		Re: unwrap modulo 2pi By: Craig Markwardt on Thu, 08 February 2001 07:43
		Re: unwrap modulo 2pi By: Wim Bouwman on Thu, 08 February 2001 01:13

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