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Re: histogram question [message #26197 is a reply to message #26139]

Thu, 09 August 2001 15:01

Jim Pendleton
Messages: 13
Registered: July 2001

Junior Member

"Bill B." <billb@attinet.com> wrote in message
news:269b6343.0108090726.e32298a@posting.google.com...
>> how can you turn the former into the latter without a loop? This is
>> somewhat similar to Pavel's running chunk index problem earlier in the
>> year. Finding an answer is not trivial. It would apply directly to
>> this problem, where the pairs are adjacent elements in the reverse
>> indices vector. Any takers?
>>
>
> I've encountered a few areas where certain logic problems cannot be
> solved without a loop in IDL. Usually, this always points to the fact
> that there are certain IDL functions that (logically) insist upon
> scalar parameters.
>
> -Bill B.
>

Okay, here's an effort using two histograms instead of one, just to
get some interest going. No visible loops, but not the sort of
stuff you put in production code. With this as a head start, let's
see the single-histogram approach.

A = [-1,3,7,12,15,18,20,20] ;The solution must work with negative and
repeating numbers
NPair = N_Elements(A)/2
MaxA = Max(A, Min = MinA)
D = MaxA - MinA
P = Lindgen(NPair)*2
H1 = Histogram(A[P], Max = MaxA, Min = MinA, R = R1)
H2 = Histogram(A[P + 1], Max = MaxA, Min = MinA, R = R2)
x1 = (R1 - MaxA)[0:D]
x2 = (R2 - MaxA)[0:D]
C = [A, ((x1 ne x2)*(Lindgen(D + 1) + MinA) > MinA) < MaxA]
C = C[Sort(C)]
C = C[Uniq(C)]
Print, C

; Loop version

B = Indgen(NPair)*2
For I = 0L, NPair - 1 Do Print, A[B[I]] + Lindgen(A[B[I] + 1]- A[B[I]] + 1)

Extra credit for minimal use of "[]" notation.

Jim P.

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[Message index]

		histogram question By: Gregory Y. Prigozhin on Wed, 08 August 2001 13:17
		Re: histogram question By: Jim Pendleton on Thu, 09 August 2001 15:01
		Re: Histogram question By: Chris Lee on Mon, 09 August 2004 07:39
		Re: Histogram question By: mperrin+news on Sun, 08 August 2004 11:52
		Re: Histogram question By: JD Smith on Tue, 10 August 2004 11:43
		Re: Histogram question By: Michael Wallace on Sun, 08 August 2004 11:28
		Re: Histogram question By: David Fanning on Sun, 08 August 2004 06:40
		Re: Histogram question By: David Fanning on Tue, 10 August 2004 12:26

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