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Re: polar interpolation [message #33625 is a reply to message #33528]

Mon, 13 January 2003 10:39

Rick Towler
Messages: 821
Registered: August 1998

Senior Member

"Thomas Gutzler" <tgutzler@ee.uwa.edu.au> wrote

> Thomas Gutzler wrote:
>>
>> I should write both functions, compare, and then decide again if I want
>> to use the conversion-method. Just wanted to know _if_ there is another
>> way to do it.
>
> I'm facing the problem now. I can see it really clear and it won't let
> me pass.
> I want an interpolated curve in polar coordinates AND equidistant
> theta-values. Since the original curve isn't a straight line it's really
> complicated to pass the correct x-values to interpol so that
> reconversion of the interpolated curve would have eqidistant
> theta-values (of type integer).
> Can anybody see and solve the problem or even give me a hint?

I might be missing something here (I usually am) but why won't simple linear
interpolation work? If it is difficult to get one of the canned routines to
work, brew your own:

Interpolate between points a and b:

iFactor = (Ti - Ta) / (Tb - Ta)

Ri = Ra + (iFactor * (Rb - Ra))

Where Ti is the Theta value where you are interpolating your radius Ri.

-Rick

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[Message index]

		polar interpolation By: Thomas Gutzler on Thu, 09 January 2003 19:20
		Re: polar interpolation By: Thomas Gutzler on Mon, 13 January 2003 17:36
		Re: polar interpolation By: Rick Towler on Mon, 13 January 2003 10:39
		Re: polar interpolation By: Thomas Gutzler on Sun, 19 January 2003 19:33
		Re: polar interpolation By: James Kuyper on Mon, 13 January 2003 09:40
		Re: polar interpolation By: Thomas Gutzler on Sun, 12 January 2003 22:43

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