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Re: last array index subscript [message #33845 is a reply to message #33731]

Fri, 31 January 2003 08:30

Doug Rowland
Messages: 12
Registered: March 2002

Junior Member

Vinay,

How does this work? I tried to wrap my brain around this one. Is it an
IDL "bug" or is there some simple rationale for IDL behaving this way?
For example, if I try to directly subscript my_array with the scalar
value 2147483647L (or any other number which is larger than the number
of elements of my_array, less one) I get

IDL> print,my_array[2147483647L]
% Attempt to subscript A with <LONG ( 2147483647)> is out of range.
% Execution halted at: $MAIN$

Why should wrapping this index value in an array suddenly make it work?

Thanks.

Doug

In <3e304dac.0@cfanews.harvard.edu> Vinay L. Kashyap wrote:
> Try
>
> value=(my_array[[2147483647L]])[0]
>
> where the "[[.]]" returns an array and the "(.)[0]" ensures that the
> output is a scalar, and 2147483647L = 2L^(31L)-1L is the largest
> possible I*4 number you can have and surely no will have an array
> bigger than that.
>
> vinay
>
--
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Doug Rowland 472 Tate Laboratory of Physics
Space Physics Laboratory 116 Church Street S.E.
School of Physics and Astronomy Minneapolis, MN
University of Minnesota 55455

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[Message index]

		Re: last array index subscript By: notspecified on Thu, 23 January 2003 12:33
		Re: last array index subscript By: kashyap on Thu, 23 January 2003 12:16
		Re: last array index subscript By: James Kuyper on Thu, 23 January 2003 10:40
		Re: last array index subscript By: Doug Rowland on Fri, 31 January 2003 08:30
		Re: last array index subscript By: hieninger on Fri, 31 January 2003 08:24

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