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Re: replace array's elemets [message #35165 is a reply to message #35158]

Sat, 17 May 2003 04:13

R.Bauer
Messages: 1424
Registered: November 1998

Senior Member

James Kuyper wrote:

> Reimar Bauer wrote:
>>
>> Roberto wrote:
>>
>>> Hi
>>> I have a 100x100 array.
>>> How can I replace an element if is different from 0?
>>> I would replace all elements different from 0 with 1.
>>> thank and sorry for the trouble.
>>> Roberto
>>
>> Dear Roberto
>>
>> I suggest something like this
>>
>> example data:
>> x=indgen(100,100)
>>
>> result:
>> result=x<1
>
> That doesn't do the right thing with negative numbers. "result=x ne 0"
> is the right choice. More generally,
>
> x[where(x ne 0)] = 1
>
> has the advantage of being more easily generalized to the case of more
> complicated search conditions, and different replacement values.
> However, it will produce an error message if no replacements are needed.

and what did you say to this:

print,(abs(x)<1)

I often use myself "where" :-)

regards
Reimar

--
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email: R.Bauer@fz-juelich.de
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[Message index]

		Re: replace array's elemets By: James Kuyper on Sat, 17 May 2003 15:15
		Re: replace array's elemets By: R.Bauer on Sat, 17 May 2003 04:13
		Re: replace array's elemets By: James Kuyper on Fri, 16 May 2003 15:19
		Re: replace array's elemets By: R.Bauer on Fri, 16 May 2003 13:45
		Re: replace array's elemets By: Liam E. Gumley on Fri, 16 May 2003 12:04
		Re: replace array's elemets By: Chris[1] on Fri, 16 May 2003 09:13
		Re: replace array's elemets By: btt on Fri, 16 May 2003 09:00

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