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Re: replace array's elemets [message #35176 is a reply to message #35171]

Fri, 16 May 2003 12:04

Liam E. Gumley
Messages: 378
Registered: January 2000

Senior Member

"Roberto" <graftons@tiscalinet.it> wrote in message
news:4ac6b3e5.0305160733.50173373@posting.google.com...
> I have a 100x100 array.
> How can I replace an element if is different from 0?
> I would replace all elements different from 0 with 1.
> thank and sorry for the trouble.

IDL> a = [0, 1, 2, 3, 0, 5, 6, 7, 0, 9]
IDL> a[*] = a ne 0
IDL> print, a, format='(10i4)'
0 1 1 1 0 1 1 1 0 1

If your array contains floating point values, you should use something like

IDL> a = [0.0, 1, 2, 3, 0, 5, 6, 7, 0, 9]
IDL> info = machar()
IDL> value = 0.0
IDL> a[*] = abs(a - value) gt info.eps
IDL> print, a, format='(10f4.1)'
0.0 1.0 1.0 1.0 0.0 1.0 1.0 1.0 0.0 1.0

Cheers,
Liam.
Practical IDL Programming
http://www.gumley.com/

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[Message index]

		Re: replace array's elemets By: James Kuyper on Sat, 17 May 2003 15:15
		Re: replace array's elemets By: R.Bauer on Sat, 17 May 2003 04:13
		Re: replace array's elemets By: James Kuyper on Fri, 16 May 2003 15:19
		Re: replace array's elemets By: R.Bauer on Fri, 16 May 2003 13:45
		Re: replace array's elemets By: Liam E. Gumley on Fri, 16 May 2003 12:04
		Re: replace array's elemets By: Chris[1] on Fri, 16 May 2003 09:13
		Re: replace array's elemets By: btt on Fri, 16 May 2003 09:00

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