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Re: how does it evaluate: y * w # A where: [message #36340 is a reply to message #36321]

Mon, 08 September 2003 17:44

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

Craig Markwardt writes:

> Hmm, David, in the manuals I've looked at, the # (matrix multiply) and
> * (multiply) operators have the *same* precedence.

Oh, whoops! I must have been looking at pointer de-referencing.
The font is a bit tiny in my on-line help, and I had misplaced
my good glasses this morning (again!). :-)

Cheers,

David

--
David W. Fanning, Ph.D.
Fanning Software Consulting, Inc.
Phone: 970-221-0438, E-mail: david@dfanning.com
Coyote's Guide to IDL Programming: http://www.dfanning.com/
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[Message index]

		Re: how does it evaluate: y * w # A where: By: iqbal_hassan on Wed, 10 September 2003 02:12
		Re: how does it evaluate: y * w # A where: By: David Fanning on Mon, 08 September 2003 17:44
		Re: how does it evaluate: y * w # A where: By: Craig Markwardt on Mon, 08 September 2003 16:28
		Re: how does it evaluate: y * w # A where: By: David Fanning on Mon, 08 September 2003 07:43
		Re: how does it evaluate: y * w # A where: By: David Fanning on Mon, 08 September 2003 07:36
		Re: how does it evaluate: y * w # A where: By: Craig Markwardt on Mon, 08 September 2003 07:26

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