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Re: Arrays with NaN values [message #41266 is a reply to message #41258]

Mon, 04 October 2004 10:08

julio
Messages: 31
Registered: December 2003

Member

Man, your code worked fine!
Very simple, very efficient...

Thanks
Julio

David Fanning <david@dfanning.com> wrote in message news:<MPG.1bca8c1aa16488e5989691@news.frii.com>...
> Julio writes:
>
>> Ok, David, but I'm using this code to put zeros in the place of Nan
>>
>> Image=(0*(where(float(finite Image[*,*],/Nan)))) + $
>> Image*(where(NOT float(finite *Image[*,*],/Nan))))
>>
>> I guess I'm not using "where" function correctly, once it doesn't
>> work.
>
> Humm. Well that code looks a little strange. :-)
>
> I think I would try something like this:
>
> index = Where(Finite(image) EQ 0, count)
> IF count NE 0 THEN image[index] = 0
>
> Cheers,
>
> David

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[Message index]

		Re: Arrays with NaN values By: Mark Hadfield on Mon, 04 October 2004 16:58
		Re: Arrays with NaN values By: David Fanning on Mon, 04 October 2004 13:35
		Re: Arrays with NaN values By: julio on Mon, 04 October 2004 10:08
		Re: Arrays with NaN values By: David Fanning on Sun, 03 October 2004 22:22
		Re: Arrays with NaN values By: julio on Sun, 03 October 2004 13:36
		Re: Arrays with NaN values By: David Fanning on Sat, 02 October 2004 23:30
		Re: Arrays with NaN values By: Paul Van Delst[1] on Tue, 05 October 2004 09:13

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