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Re: Arrays with NaN values [message #41277 is a reply to message #41272]

Sun, 03 October 2004 13:36

julio
Messages: 31
Registered: December 2003

Member

Ok, David, but I'm using this code to put zeros in the place of Nan

Image=(0*(where(float(finite Image[*,*],/Nan)))) + $
Image*(where(NOT float(finite *Image[*,*],/Nan))))

I guess I'm not using "where" function correctly, once it doesn't
work.
What could be the problem? I must retain the array size, I just need
to change Nan for zeros or other value.

Regards,
Julio

David Fanning <david@dfanning.com> wrote in message news:<MPG.1bc94a59bb2414b998968f@news.frii.com>...
> Julio writes:
>
>> I need to manipulate arrays with some NaN values inside. How can I put
>> zero values in the place of the NaN values??
>
> Here is an article that describes how to find them, so
> you can change them:
>
> http://www.dfanning.com/tips/check_nan.html
>
> Cheers,
>
> David

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[Message index]

		Re: Arrays with NaN values By: Mark Hadfield on Mon, 04 October 2004 16:58
		Re: Arrays with NaN values By: David Fanning on Mon, 04 October 2004 13:35
		Re: Arrays with NaN values By: julio on Mon, 04 October 2004 10:08
		Re: Arrays with NaN values By: David Fanning on Sun, 03 October 2004 22:22
		Re: Arrays with NaN values By: julio on Sun, 03 October 2004 13:36
		Re: Arrays with NaN values By: David Fanning on Sat, 02 October 2004 23:30
		Re: Arrays with NaN values By: Paul Van Delst[1] on Tue, 05 October 2004 09:13

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