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Re: a polygon version of polyline.. [message #41333 is a reply to message #41290]

Thu, 07 October 2004 20:50

rdsheu
Messages: 3
Registered: September 2004

Junior Member

Dear all,

I propose an alternative way(a little dirty..) for your information.
-_-||

Rendy
------------------------------------------------------------ ------
Pro tPipeline
; a test procedure for 3D pipeline (a dirty way)

NN = 20 ; color number
R = 0.50

thick0 = 5

t = findgen(361)*!DTOR*4.
x = R*cos(t)
y = R*sin(t)
z = -1 + findgen(361)/360.*2.

oLine1 = objarr(NN)

For i=0, NN-1 do $
oLine1[i] = obj_new('IDLgrPolyline', x, y, z, thick=1.+9./NN*i,
color=[255-I*10,20,20])

oLine2 = objarr(NN)
For i=0, NN-1 do $
oLine2[i] = obj_new('IDLgrPolyline', [0, 0], [0,0], [-1.5,1.5],
thick=1.+9./NN*i, color=[20,255-I*10,255-I*10])

oModel = obj_new('IDLgrModel')
oModel -> Add, oLine1
oModel -> Add, oLine2

xobjview, oModel

End

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[Message index]

		Re: a polygon version of polyline.. By: george on Fri, 01 October 2004 08:56
		Re: a polygon version of polyline.. By: Rick Towler on Thu, 30 September 2004 16:22
		Re: a polygon version of polyline.. By: george on Thu, 30 September 2004 09:15
		Re: a polygon version of polyline.. By: Rick Towler on Wed, 29 September 2004 17:21
		Re: a polygon version of polyline.. By: Mark Hadfield on Wed, 29 September 2004 16:54
		Re: a polygon version of polyline.. By: Randall Skelton on Sat, 02 October 2004 11:55
		Re: a polygon version of polyline.. By: rdsheu on Thu, 07 October 2004 20:50

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