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Re: Positions in 3-d [message #43821 is a reply to message #43820]

Fri, 29 April 2005 11:35

Xavier Llobet
Messages: 7
Registered: April 2005

Junior Member

In article <1114797354.327497.219120@f14g2000cwb.googlegroups.com>,
panblosky@gmail.com wrote:

> Hi, I have the following problem. I have a 3xn array, where n can go
> from 32000 to 16.000.000. This array represents positions in space, or
> just lets say x,y,z. The numbers go from 0 to 1. I have a cube of sides
> 1. I divide that cube into a 3-D grid, where my gridsize can go from 32
> to 512 in every direction (depends on how big I want the grid). So, in
> 1-D, the box is going to be divided in:
>
> lon=findgen(n0)/float(n0-1)*float(boxsize)/boxsize
>
> where n0 is the size of the grid (for example, 128) and boxsize is 1.
> The same thing goes for the other two dimensions.
> Now, I want to find what points (x,y,z) lies in which gridcell
> (between lon[i+1] and lon[i] in every direction).
> If I do it with a for loop (together with a where), it will take for
> ever. I have tried sorting, but I just can't get it right. Does
> somebody knows a fast way?
> Thanks,
>
> Pablo

Look at the HISTOGRAM function, REVERSE_INDICES keyword.

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[Message index]

		Re: Positions in 3-d By: K. Bowman on Mon, 02 May 2005 10:38
		Re: Positions in 3-d By: panblosky on Mon, 02 May 2005 09:05
		Re: Positions in 3-d By: K. Bowman on Fri, 29 April 2005 14:45
		Re: Positions in 3-d By: Xavier Llobet on Fri, 29 April 2005 11:35

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