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Re: Concatenating arrays [message #45372 is a reply to message #31266]

Sun, 04 September 2005 12:11

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

RPF writes:

> me...
> If I have a = [2 3] and i wish to repeat these two elements for say 1000
> times so my final array is 2000 elements long is there a quick way?

You want to read the Dimensional Juggling Tutorial:

http://www.dfanning.com/documents/tips.html#Tutorials

Try this:

a = [2, 3]
b = Reform(Rebin(a, 2, 1000), 2000)

> Also is there an easy way to make an upper triangular matrix i.e.
> make all entries below the diagonal zero ?

Probably. There always is. But the exactly method eludes me at
the moment. :-)

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/

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[Message index]

		Concatenating arrays across chosen dimension By: Dick Jackson on Tue, 25 June 2002 15:05
		Re: Concatenating arrays By: K. Bowman on Mon, 05 September 2005 07:08
		Re: Concatenating arrays By: David Fanning on Sun, 04 September 2005 12:11
		Re: Concatenating arrays By: Wonko[3] on Sun, 04 September 2005 12:06

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