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Re: transforming a row vector into a column vector (continued) [message #46029 is a reply to message #46022]

Tue, 25 October 2005 07:48

peter.albert@gmx.de is currently offline

peter.albert@gmx.de
Messages: 108
Registered: July 2005

Senior Member

Hi Francois,

well, the answer is already in your post :-)

What does the output of size(b) actuall mean?
The first "2" tells us that b is 2-dimensional.
The following "1" tells us that the number of columns (the x-dimension)
is 1.
The following "4" tells us that the number of rows (the y-dimension) is
4.

Voila, that's the definition of a column vector, isn't it? It has one
column and n rows.

IDL does not know different types of vectors, a vector in its
1-dimensional form always is a row vector.

As for your second question, again the answer is in your post: The
"possibility for knowing what type an array is" is the SIZE() command:

case 1 of
(size(array))[0] eq 1:print, "This array is a row vector"
(size(array))[0] eq 2: print, (size(array))[1] eq 1 $
? "This array is a column vector" $
: "This array really is a 2D array"
else: print, "This array has even more dimensions"
endcase

Cheers,

Peter

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[Message index]

		Re: transforming a row vector into a column vector (continued) By: Mark Hadfield on Tue, 25 October 2005 14:39
		Re: transforming a row vector into a column vector (continued) By: peter.albert@gmx.de on Tue, 25 October 2005 07:48

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