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Re: keyword_set([0]) [message #48069 is a reply to message #48059]

Mon, 20 March 2006 15:49

vlk.astro
Messages: 11
Registered: March 2006

Junior Member

JD Smith wrote:

>
> IDL> print, size(b,/N_DIMENSIONS) gt 0 OR keyword_set(b)

Unfortunately, upon further investigation, this doesn't quite work.
The behavior I am looking for is (sorry I wasn't clearer before): if
A=0 and B=[0], then expr(A)=0 and expr(B)=1 in all versions of IDL (for
backwards compatibility and all that)

instead, 5.3 and 6.2 never match up properly --

v5.3 v6.2 expr()
0 0 keyword_set(A)
1 0 keyword_set(B)

1 0 size(A,/dim) gt 0 OR keyword_set(A)
1 1 size(B,/dim) gt 0 OR keyword_set(B)

i.e., if it works in 5.3, it doesn't in 6.2, and vice versa.

Vinay

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[Message index]

		Re: keyword_set([0]) By: vlk.astro on Tue, 21 March 2006 13:18
		Re: keyword_set([0]) By: JD Smith on Tue, 21 March 2006 11:24
		Re: keyword_set([0]) By: vlk.astro on Mon, 20 March 2006 15:49
		Re: keyword_set([0]) By: vlk.astro on Mon, 20 March 2006 13:52
		Re: keyword_set([0]) By: vlk.astro on Mon, 20 March 2006 13:46
		Re: keyword_set([0]) By: Andrew Cool on Mon, 20 March 2006 13:19
		Re: keyword_set([0]) By: JD Smith on Mon, 20 March 2006 12:24

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