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Re: double precision? [message #49694]

Fri, 11 August 2006 13:17

Chris[2]
Messages: 39
Registered: August 2003

Member

You still need the "d" after the number, to make sure it is double
precision:

IDL> a = 1.24500000476837d

IDL> print,a,format='(f25.16)'

1.2450000047683700

-Chris

<adisn123@yahoo.com> wrote in message
news:1155323735.947393.276430@m73g2000cwd.googlegroups.com.. .
> I tried your way, but IDL prints
>
> IDL> a = 1.24500000476837
> IDL> print,a,format='(f50.25)'
> 1.2450000047683715820312500
> IDL>
>
> Furthermore, the variable a is constantly used throughout the whole
> program.
> Is there a way that all the other calculation use the same a and makes
> output in the same
> decimal points?
>
>
>
> R.G. Stockwell wrote:
>> <adisn123@yahoo.com> wrote in message
>> news:1155241088.452911.315540@i3g2000cwc.googlegroups.com...
>>> Hi,
>>>
>>> The value that I want to keep in a variable, a, is
>>> 1.24500000476837.
>>> After I define as
>>> IDL> a = 1.24500000476837
>>> then, print, a
>>> IDL> print, a
>>> IDL> 1.2450000
>>> so, I tried
>>> IDL> a = 1.24500000476837d ;; to make it as a double precision, but
>>> IDL prints
>>> IDL> help, a
>>> A DOUBLE = 1.2450000
>>> IDL> print, a
>>> 1.2450000
>>>
>>>
>>> How can I keep all those decimal points?
>>> I thought double precision can express up to 14 decimal places of
>>> significant points?
>>
>>
>> Try
>> IDL> print,a,format='(f50.25)'
>> 1.2450000047683700000000000
>>
>> Cheers,
>> bob
>

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[Message index]

		Re: double precision? By: Chris[2] on Fri, 11 August 2006 13:17
		Re: double precision? By: adisn123 on Fri, 11 August 2006 12:15
		Re: double precision? By: news.qwest.net on Thu, 10 August 2006 13:35
		Re: double precision? By: adisn123 on Mon, 14 August 2006 09:45

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