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Re: Multiply matrix [message #52642 is a reply to message #52638]

Sun, 18 February 2007 07:12

L. Testut
Messages: 16
Registered: January 2006

Junior Member

On 16 fév, 21:36, "hradilv" <hrad...@yahoo.com> wrote:
> On Feb 16, 2:24 pm, "Bob Crawford" <Snowma...@gmail.com> wrote:> > filter = [[filter*0],[filter*0],[filter]]
>>> hnew = h*filter
>
>> That would zero out all the lat & lon values wouldn't it?
>
>> filter = [[filter/filter],[filter/filter],[filter]]
>
>> should retain the lat & lon values.
>
> Of course, I was trying to do two things at once...

Sorry it doesn't work in my case I want to avoid this loop:

FOR I=0,nz-1 DO
z[indgen(nx),indgen(ny),I]=Z[indgen(nx),indgen(ny),I]*filter

I have a H[nx,ny,nz] where nz is the time. So i have nz field in time
that i want to multiply by a filter of size nz.

Is it possible to avoid this loop ?

Thanks
Laurent

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[Message index]

		Re: Multiply matrix By: Wox on Mon, 19 February 2007 01:27
		Re: Multiply matrix By: Wox on Mon, 19 February 2007 01:26
		Re: Multiply matrix By: L. Testut on Sun, 18 February 2007 07:12
		Re: Multiply matrix By: Vince Hradil on Fri, 16 February 2007 13:36
		Re: Multiply matrix By: Bob[3] on Fri, 16 February 2007 12:24
		Re: Multiply matrix By: Vince Hradil on Fri, 16 February 2007 12:08

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