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Re: Pasting subarray into array with compound assignment [message #53601 is a reply to message #53596]

Fri, 20 April 2007 14:34

Vince Hradil
Messages: 574
Registered: December 1999

Senior Member

On Apr 20, 12:29 pm, hradilv <hrad...@yahoo.com> wrote:
> On Apr 19, 7:37 pm, "m.avd...@gmail.com" <m.avd...@gmail.com> wrote:
>
>> i'm trying to use the advantage of "+=" when reshaping 2d array to 1d
>
>> Can anyone tell me why the following produce different values?
>> (difference in shape and type of the results is not a problem)
>
>> a1=indgen(3,7) & for i=0,2 do a2[0,i*2]+=a1[i,*] & print,a2
>
>> a1=indgen(3,7) & a2=intarr(3,11) & for i=0,2 do a2[i,i*2]=a1[i,*] &
>> a2=total(a2,1) & print,a2
>
>> thanks,
>> max
>
> Decompose the += into a2[0,2] = a2[0,2] + a1[1,*] (for i=1, for
> instance).
>
> The RHS is 6 + a1[1,*] which is transpose(7,10,13,16,19,22,25). This
> then gets placed into the a2 array at position [0,2]
>
> Same for i=2...

This will work:
a1=indgen(3,7) & a2=intarr(3,11) & for i=0,2 do
a2[0,i*2:i*2+7-1]+=a1[i,*] & print,a2

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[Message index]

		Re: Pasting subarray into array with compound assignment By: m.avdeev@gmail.com on Sat, 21 April 2007 06:21
		Re: Pasting subarray into array with compound assignment By: Vince Hradil on Fri, 20 April 2007 14:34
		Re: Pasting subarray into array with compound assignment By: Vince Hradil on Fri, 20 April 2007 10:29
		Re: Pasting subarray into array with compound assignment By: Vince Hradil on Mon, 23 April 2007 09:25

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