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Re: Why does '[1,2,3] EQ [2]' yield zero but '[1,2,3] EQ 2' yield [0,1,0] ? [message #54363 is a reply to message #54361]

Fri, 01 June 2007 21:29

sujian
Messages: 10
Registered: May 2007

Junior Member

On Jun 1, 10:18 pm, Gianguido Cianci <gianguido.cia...@gmail.com>
wrote:
> Hi all,
>
> The post title says it all. I thought "everything" in IDL was an
> array, but using [2] and 2 with relational operators is not
> equivalent...
>
> I searched the doc and newsgroup for quite a while, but obviously I
> did not come up with search terms that are specific enough.
>
> It took me a while to track this down in some code I was writing. My
> bug is now fixed *but* I don't understand why exactly. And we all know
> voodoo and IDL don't mix :-) can somebody clarify please?
>
> Many thanks,
> Gianguido
>
> PS: I have a feeling this issue came up not too long ago, just
> couldn't find it. Sorry :-( Feel free to dispense with this question
> with a link.

my guess:

[1,2,3] EQ [2] compares two sets, one with 3 elements and the other 1.

[1,2,3] EQ 2 compares each element of the first set with number 2.

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[Message index]

		Re: Why does '[1,2,3] EQ [2]' yield zero but '[1,2,3] EQ 2' yield [0,1,0] ? By: cgguido on Sat, 02 June 2007 14:13
		Re: Why does '[1,2,3] EQ [2]' yield zero but '[1,2,3] EQ 2' yield [0,1,0] ? By: wlandsman@jhu.edu on Sat, 02 June 2007 05:44
		Re: Why does '[1,2,3] EQ [2]' yield zero but '[1,2,3] EQ 2' yield [0,1,0] ? By: sujian on Fri, 01 June 2007 21:29

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