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Re: making a checkerboard array? [message #56020 is a reply to message #55935] Tue, 25 September 2007 15:59 Go to previous messageGo to previous message
David Fanning is currently offline  David Fanning
Messages: 11724
Registered: August 2001
Senior Member
Jean H writes:

> IDL> nx=20
> IDL> ny=20
> IDL> l=lindgen(nx,ny)
> IDL> l=(l mod (nx*2) lt nx) XOR (l/nx mod (ny*2) ge ny)
> IDL> print,l

If there is a question in there, I think this is the answer:

IDL> nx=20
IDL> ny=20
IDL> l =lindgen(nx, ny)
IDL> l=(l mod (2) lt 1) XOR (l/nx mod (2) ge 1)
IDL> print, l
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1
1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0
1 0
0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1
0 1

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")
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