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Re: Q: IDL benchmarks [message #5876 is a reply to message #5827] Tue, 27 February 1996 00:00 Go to previous messageGo to previous message
Mark Baldwin is currently offline  Mark Baldwin
Messages: 1
Registered: February 1996
Junior Member
The following is from a Pentium 133 w/ SCSI disk, 32 Mb RAM, running IDL 4.01, PCI
bus. Could anyone post the result for a Pentium Pro 200?

NOTE: This is NOT the same time_test from PV_WAVE! E.G. test #1 for IDL is run 1
million times, while PV_WAVE runs it 10,000 times.

IDL> time_test
1 0.431000 Empty For loop, 1 million times
2 0.601000 Call empty procedure (1 param) 100,000 times
3 0.461000 Add 100,000 integer scalars and store
4 0.490000 25,000 scalar loops each of 5 ops, 2 =, 1 if)
5 0.501000 Mult 512 by 512 byte by constant and store, 10 times
6 0.240000 Shift 512 by 512 byte and store, 10 times
7 0.381000 Add constant to 512 x 512 byte array and store, 10 times
8 0.431000 Add two 512 by 512 byte images and store, 10 times
9 0.691000 Mult 512 by 512 floating by constant and store, 10 times
10 0.711000 Add constant to 512 x 512 floating and store, 10 times
11 0.891000 Add two 512 by 512 floating images and store, 10 times
12 0.210000 Invert a 100 by 100 random matrix
13 0.641000 Transpose 256 x 256 byte, FOR loops
14 0.100000 Transpose 256 x 256 byte, row and column ops
15 0.0200000 Transpose 256 x 256 byte, transpose function
16 1.80200 Log of 100,000 numbers, FOR loop
17 0.321000 Log of 100,000 numbers, vector ops
18 1.15100 Add two 100000 element floating vectors, FOR loop
19 0.0500001 Add two 100000 element floating vectors, vector op
20 0.320000 65536 point real to complex FFT
21 0.260000 Smooth 512 by 512 byte array, 5x5 boxcar
22 0.160000 Smooth 512 by 512 floating array, 5x5 boxcar
23 0.430000 Write and read 10 512 by 512 byte arrays
11.2940=Total Time, 0.34653037=Geometric mean, 23 tests.

Mark Baldwin
Northwest Research Associates
Bellevue, WA USA
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