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Re: How to extract sub-string from array [message #61759 is a reply to message #61697] Tue, 29 July 2008 01:33 Go to previous messageGo to previous message
Ian Dean is currently offline  Ian Dean
Messages: 26
Registered: January 2000
Junior Member
"F�LDY Lajos" <foldy@rmki.kfki.hu> wrote in message
news:Pine.LNX.4.64.0807281111470.17704@bifur.rmki.kfki.hu...
>
> On Mon, 28 Jul 2008, Ian Dean wrote:
>
>> Hi,
>> I've got an array such as ['Test_data;01', 'Test_data;005',
>> 'New_dat;100','Old_dat'....]
>>
>> What I'd like to do but haven;t achieved is create an array of the
>> extension
>> past the ';'
>> i.e. ['01','005','100',''....]
>> I've tried this:
>>
>> semi_colon = STREGEX(Data_array, ';')
>> ; This gives an array of positions [9, 9, 7,-1...]
>>
>> I can replace the -1s with string lengths easily enough giving [9, 9, 7,
>> 7...]
>> However, I can't seem to extract the sub-strings
>> I tried
>> Extension = STRMID(Data_array, semi_colon + 1)
>> but this gives me a 2-d array and no clue which elements I require.
>> I suspect that there is some arcane use of histogram, but I am not brave
>> enough to try.
>>
>> I know why the STRMID is failing, because the help says so, because both
>> arguments are arrays.
>> Looping though the list is not an option as in reality I have an array
>> length in the order of 500,000
>>
>> Any help would be appreciated,
>> Regards,
>> Ian
>
>
> Try this: STRMID(STREGEX(Data_array, ';.*', /extract), 1)
>
> regards,
> lajos
>
Thanks to all. It's so simple when you know how!!
Regards,
Ian
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