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Re: Counting the lengths of continuous numbers in an array [message #61968 is a reply to message #61824]

Mon, 11 August 2008 06:08

Brian Larsen
Messages: 270
Registered: June 2006

Senior Member

>> IDL> aa = [a[0],a,0]
>> IDL> b = where( (aa-shift(aa,1)) ne 1)
>> IDL> c = b-shift(b,1)
>> IDL> print, c[1:*]
>> 4 2 1 2 3

While I can't seem to find it this second my tired and jet lagged
brain is telling me that there is an built-in idl function to
calculate array[*]-array[1:*], which should be equivalent to above.
Now to remember the function.

Cheers,

Brian

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[Message index]

		Re: Counting the lengths of continuous numbers in an array By: andy.mcneel on Fri, 08 August 2008 14:41
		Re: Counting the lengths of continuous numbers in an array By: mankoff on Fri, 08 August 2008 14:28
		Re: Counting the lengths of continuous numbers in an array By: Brian Larsen on Mon, 11 August 2008 06:08

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