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Re: Compute area between curves [message #62927 is a reply to message #62821] Wed, 15 October 2008 13:37 Go to previous messageGo to previous message
frankosuna is currently offline  frankosuna
Messages: 31
Registered: February 2008
Member
Ok, I will try to explain what is going on.

I have a 3D wireframe model of Saturn and its rings. This wireframe
(which is superimposed over an image) is shifted and rotated
to match an image. The wireframe contains rings of Saturn and the
image contains the edges to where those rings belong. Scientists
tweak the wireframe so that it matches those edges, thus correcting
spacecraft pointing vectors. This is called C-Smithing or Camera
Smithing.

http://frankosuna.googlepages.com/wireframe2.jpg
This image is taken from the wireframe. I used region growing so that
when the user clicks on a ring in the wireframe, it selects that ring
(so that they can use
that ring to match it to an edge) and create this image.

http://frankosuna.googlepages.com/edgeDetect2.jpg
This image is created by utilizing a saturn image that contains many
features from saturn(like the edges of its rings). This in fact is an
edge to a ring from Saturn.
Region growing is used when the user selects a point in the image(this
should be the corresponding ring from the wireframe). Based on that
point where the user clicks, it region grows
that section and creates this image.

I have an algorithm that tries to match two images of the same scene
but different perspectives meaning that one image might be scaled,
rotated, or shifted differently than the other image.

The values taken from this algorithm are used to correct the wireframe
so that we can match it to the corresponding edge and therefor
correcting the spacecraft pointing vectors.

I need to come up with some measurement to see how close the edge
detected ring from the image and the ring from the wireframe are. They
are ellipses and they do cross since we're trying to get them as close
as possible.

I hope this clears things up.

Thanks for taking time to respond with such detailed answers,

Frank
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