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Re: how can i get an [n,1] array without reform? [message #63898 is a reply to message #63826]

Fri, 21 November 2008 07:28

mccreigh
Messages: 13
Registered: January 2008

Junior Member

> Hi
>
> that can be also solved by
>
> if size(a, /n_dim) eq 1 and size(b, /n_dim) eq 1 then $
> c = [[a],[b]] $
> else ....
>
> cheers
> Reimar

In my version of IDL (6.4.1), that gives a column vector of dimension
[1,2]. Which is not a solution, no free beer for you. Try again! :)

But that's OK, i will accept that it cant be done without reform.
Fortunately, in my code i already have a surrogate variable which
implies the dimension of a and b. But I still have to test (n eq
max-1) unnecessarily in all but one case, seems like a waste.

Should we all avoid using and concatenating column vectors then and
just use row vectors? I guess I could just put these in an array right
off the bat and avoid concatenation all together. That seems like it
would be faster anyway, if i'm really concerned with speed.

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[Message index]

		Re: how can i get an [n,1] array without reform? By: Vince Hradil on Thu, 20 November 2008 20:58
		Re: how can i get an [n,1] array without reform? By: R.Bauer on Thu, 20 November 2008 15:25
		Re: how can i get an [n,1] array without reform? By: mccreigh on Thu, 20 November 2008 13:54
		Re: how can i get an [n,1] array without reform? By: mccreigh on Thu, 20 November 2008 10:20
		Re: how can i get an [n,1] array without reform? By: mccreigh on Fri, 21 November 2008 07:28

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