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Re: How to find second minimum elements in an array in IDL? [message #64675 is a reply to message #64672]

Wed, 14 January 2009 07:38

Brian Larsen
Messages: 270
Registered: June 2006

Senior Member

or something like,
IDL> X=[9,2,3,5,1,6,8,4,7]
IDL> ind1 = where(X eq min(X), comp=comp)
IDL> ind2 = where(x[comp] eq min(x[comp]))
IDL> print, x[ind1], x[ind2]
1
2

be VERY careful that ind2 is referring to the array x[comp] NOT the
array x.

Or one could use sort to find the value:
IDL> xs=x[sort(x)]
IDL> xu=uniq(xs)
% Compiled module: UNIQ.
IDL> ind=where(xu eq 1)
IDL> print, xu[1]
1

and there where to find the index of the value in x

Cheers,

Brian

------------------------------------------------------------ --------------
Brian Larsen
Boston University
Center for Space Physics
http://people.bu.edu/balarsen/Home/IDL

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[Message index]

		Re: How to find second minimum elements in an array in IDL? By: Carsten Lechte on Wed, 14 January 2009 07:45
		Re: How to find second minimum elements in an array in IDL? By: Hu on Wed, 14 January 2009 07:41
		Re: How to find second minimum elements in an array in IDL? By: Brian Larsen on Wed, 14 January 2009 07:41
		Re: How to find second minimum elements in an array in IDL? By: Brian Larsen on Wed, 14 January 2009 07:38
		Re: How to find second minimum elements in an array in IDL? By: David Fanning on Wed, 14 January 2009 07:31

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