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faster then where possible? [message #66276]

Thu, 07 May 2009 08:06

rogass
Messages: 200
Registered: April 2008

Senior Member

Hi,
i'm searching for some alternative approaches to compute the following
"much" faster:

-> matrix1 has m columns and n rows, matrix2 has 2 columns and n rows
-> the values in matrix2 are NOT in matrix1, but within the min-max-
range of matrix1

szm1=size(matrix1,/dimensions)
szm2=size(matrix2,/dimensions)
index={ind:ptr_new()}
indices=replicate(index,szm2[1])

for j=0ull,szm1[1] do begin
helpindex= where(matrix1[*,j] ge matrix2[0,j] and matrix1[*,j] le
matrix2[1,j],c)
if c gt 0 then begin
indices[j] = ptr_new(uintarr(c))
(*indices)[j]=helpindex
endif else continue
endfor

It seems to be a typical Nearest-Neighbor-Problem, but all alternative
approaches I tried were always slower. Maybe someone here has a good
idea?

Thank you and best regards

Christian

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[Message index]

		faster then where possible? By: rogass on Thu, 07 May 2009 08:06
		Re: faster then where possible? By: rogass on Mon, 11 May 2009 02:00
		Re: faster then where possible? By: Conor on Fri, 08 May 2009 07:14
		Re: faster then where possible? By: Jeremy Bailin on Fri, 08 May 2009 04:58

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