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Re: Using where() on slices of data cubes [message #68334 is a reply to message #68327]

Tue, 20 October 2009 07:34

lecacheux.alain
Messages: 325
Registered: January 2008

Senior Member

> This method avoids the need for any duplication:
>
> w=where(cube[1,*,*] lt 0)
> sz=size(cube,/dim)
> cube=reform(cube,[sz[0],sz[1]*sz[2]],/overwrite)
> cube[1,w]=1e24
> cube=reform(cube,sz,/overwrite)
>
> regards,
> Greg

Is'nt this more efficient ?
cube[1,*,*] = 1e24*(cube[1,*,*] lt 0) + cube[1,*,*]*(cube[1,*,*] ge
0)

alx.

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[Message index]

		Re: Using where() on slices of data cubes By: David Fanning on Tue, 20 October 2009 13:32
		Re: Using where() on slices of data cubes By: JDS on Tue, 20 October 2009 13:03
		Re: Using where() on slices of data cubes By: David Fanning on Tue, 20 October 2009 13:03
		Re: Using where() on slices of data cubes By: Foldy Lajos on Tue, 20 October 2009 07:26
		Re: Using where() on slices of data cubes By: greg.addr on Tue, 20 October 2009 09:18
		Re: Using where() on slices of data cubes By: Paul Van Delst[1] on Tue, 20 October 2009 08:00
		Re: Using where() on slices of data cubes By: penteado on Tue, 20 October 2009 07:39
		Re: Using where() on slices of data cubes By: lecacheux.alain on Tue, 20 October 2009 07:34
		Re: Using where() on slices of data cubes By: greg.addr on Tue, 20 October 2009 07:20
		Re: Using where() on slices of data cubes By: Conor on Tue, 20 October 2009 06:20
		Re: Using where() on slices of data cubes By: David Fanning on Tue, 20 October 2009 06:03
		Re: Using where() on slices of data cubes By: JDS on Wed, 21 October 2009 14:52

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