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Re: renaming a variable without making a copy [message #69160 is a reply to message #68975]

Fri, 11 December 2009 03:51

R.Bauer
Messages: 1424
Registered: November 1998

Senior Member

alx schrieb:
> On 10 dï¿½c, 17:30, alx <lecacheux.al...@wanadoo.fr> wrote:
>> On 10 dï¿½c, 16:36, Reimar Bauer <R.Ba...@fz-juelich.de> wrote:
>>
>>> alx schrieb:
>>> IDL> a=findgen(2,2)
>>> IDL> b=dblarr(4)
>>> IDL> reads,a,b
>>> IDL> print,b
>>> 0.0000000 1.0000000 2.0000000 3.0000000
>>> btw. just seen that reads, 1 seems to be valid, but what does it do?
>>
> Unfortunately, that does not work as you said: "reads" (cf. IDL doc)
> converts
> your 'a' array to an array of strings, then 'read' it to 'b' by using
> implicit formatting.
> That is actually not a "memory read" and, likely, does not work with
> structures.
>
>

what is that doing then?

IDL> a=bindgen(3)
IDL> b=ptr_new({s:intarr(3)})
IDL> reads,a,*b
IDL> print,*b
{ 0 1 2

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[Message index]

		renaming a variable without making a copy By: David Higgins on Tue, 08 December 2009 03:51
		Re: renaming a variable without making a copy By: lecacheux.alain on Thu, 10 December 2009 08:56
		Re: renaming a variable without making a copy By: R.Bauer on Fri, 11 December 2009 03:51
		Re: renaming a variable without making a copy By: lecacheux.alain on Thu, 10 December 2009 08:30
		Re: renaming a variable without making a copy By: R.Bauer on Thu, 10 December 2009 07:36
		Re: renaming a variable without making a copy By: lecacheux.alain on Thu, 10 December 2009 02:31
		Re: renaming a variable without making a copy By: penteado on Fri, 11 December 2009 08:38
		Re: renaming a variable without making a copy By: lecacheux.alain on Fri, 11 December 2009 05:22

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