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Re: Readf [message #70208 is a reply to message #57392]

Fri, 19 March 2010 05:52

Gray
Messages: 253
Registered: February 2010

Senior Member

On Mar 19, 7:51 am, bing999 <thibaultga...@gmail.com> wrote:
> Hi,
>
> i have written a file in fortran this way:
>
> write(444,'(e14.6,1x,e14.6,1x,e14.6)',advance='yes') A, B, C
>
> where A has a value of 2.10^60 and the other ones 0.0000000
>
> The file is printed correctly but when i want to read it with IDL:
>
> readf,11,format='(e14.6,1x,e14.6,1x,e14.6)', A, B, C
>
> It displays Inf for A and 0.0000000 for B and C.
>
> However, it is the same format I don't understand why it prints Inf
> for A ( even if i initialize A = 0.d0)
>
> If somebody could help, it would really help me !
> Thanks

The problem is that you're reading it in as a float, which has a
maximum value of 10^38. You need to read them in as type double.

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[Message index]

		readf,1,format= ...... By: woopik on Sat, 08 December 2007 13:18
		Re: readf,1,format= ...... By: David Fanning on Mon, 10 December 2007 06:35
		Re: readf,1,format= ...... By: woopik on Tue, 11 December 2007 06:01
		Re: readf,1,format= ...... By: woopik on Mon, 10 December 2007 06:11
		Re: readf,1,format= ...... By: David Fanning on Sun, 09 December 2007 10:06
		Re: readf,1,format= ...... By: woopik on Sun, 09 December 2007 09:57
		Re: readf,1,format= ...... By: woopik on Sun, 09 December 2007 08:40
		Re: readf,1,format= ...... By: David Fanning on Sun, 09 December 2007 08:07
		Re: readf,1,format= ...... By: Vince Hradil on Sun, 09 December 2007 07:49
		Re: readf,1,format= ...... By: woopik on Sun, 09 December 2007 06:50
		Re: readf,1,format= ...... By: Vince Hradil on Sun, 09 December 2007 05:45
		Re: Readf By: Maarten[1] on Fri, 19 March 2010 05:54
		Re: Readf By: Gray on Fri, 19 March 2010 05:52
		Re: Readf By: Maarten[1] on Fri, 19 March 2010 05:51

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