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Re: how many array elements with a certain value in a row [message #70271 is a reply to message #70270] Thu, 01 April 2010 06:56 Go to previous messageGo to previous message
Jeremy Bailin is currently offline  Jeremy Bailin
Messages: 618
Registered: April 2008
Senior Member
On Apr 1, 9:48 am, Chris W <cwood1...@gmail.com> wrote:
> On Apr 1, 7:49 am, Jeremy Bailin <astroco...@gmail.com> wrote:
>
>> Does anyone have a nice simple efficient solution to this problem (I
>> have a simple inefficient solution and a vague sketch in my mind of a
>> convoluted but probably efficient solution):
>
>> I have an image in which many pixels are saturated (=65535, they're
>> short unsigned). I want to treat each set of consecutive saturated
>> pixels in a row as a single unit and know how many saturated pixels in
>> a row there are. So I would like to have a list that contains (a) the
>> rightmost pixel of each set of consecutive saturated pixels, and (b)
>> how many saturated pixels there were in the set.
>
>> Any suggestions?
>
>> -Jeremy.
>
> create an array the same size as the image, with values equal to the x
> index ([0,1,2,3,4,5,.....]:
>
> x = indgen(512)
> rx = rebin(x,512,512)
>
> ;;create a mask
> mask = image eq 65535
>
> ;; index values of the mask
> rxmask = rx*mask
>
> rightvalues = max(rxmask, dimension=1)
>
> number_in_rows = total(mask, 1)

No, that won't work - it will only pick up one set per row. There
could be none or many sets in a ny given row.

-Jeremy.
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