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Re: Butterworth Band-Pass Filter [message #73911 is a reply to message #73910] Sun, 12 December 2010 09:19 Go to previous messageGo to previous message
David Fanning is currently offline  David Fanning
Messages: 11724
Registered: August 2001
Senior Member
burton449 writes:

> I dont think you can create a High-Pass filter the way you explain it
> like your last post or like you explain in the article because you
> have the division by 0 error when you put the Dist function in
> denominator... even in your example with dist(248) you have the same
> error...

Oh, right. Good point. In the book I actually
used a Gaussian high-pass filter, but it should
have had the same problem. Humm. I'll have to
look at that more closely. I certainly got
nice looking output. I wonder why... :-(

Well, you could do something like this:

(Dist(s[0],s[1]) > 1e-6)

> Is it possible to have a look at this book? :)

Probably not. My little experiment to make
draft chapters available was a dismal failure.
Lots of people downloaded the chapters, but
only one person sent me any comments. They were
too embarrassed, I guess. :-(

I will be looking for people willing to read the
book and help me find typos and these kind of
errors, though. Probably after the first of the
year. Would you be interested in that?

Cheers,

David

--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")
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