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Re: round to x number of decimals within floating point value? [message #74335 is a reply to message #74333]

Thu, 13 January 2011 15:55

penteado
Messages: 866
Registered: February 2018

Senior Member
Administrator

On Jan 13, 5:35 pm, David Fanning <n...@dfanning.com> wrote:
> Snow53 writes:
>> I need to round the values within a file to three decimal places. For
>> example, 0.00053335 would become 0.001.
>> I also have many NaNs within the file.
>
> goodval = where(array EQ Finite(), count)
> if count gt 0 then begin
> array[gooval] = Float(Round(array[goodval]*1000)/1000.)
> endif

Is this a non-default finite()? The one I know takes an argument,
returning whether the elements are finite numbers (not infinity or
NaN).

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[Message index]

		Re: round to x number of decimals within floating point value? By: David Fanning on Thu, 13 January 2011 16:07
		Re: round to x number of decimals within floating point value? By: penteado on Thu, 13 January 2011 15:55
		Re: round to x number of decimals within floating point value? By: Snow53 on Thu, 13 January 2011 11:40
		Re: round to x number of decimals within floating point value? By: David Fanning on Thu, 13 January 2011 11:35
		Re: round to x number of decimals within floating point value? By: Kenneth P. Bowman on Fri, 14 January 2011 07:16

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