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Re: A little help [message #80058 is a reply to message #80057] Thu, 10 May 2012 04:09 Go to previous messageGo to previous message
Yngvar Larsen is currently offline  Yngvar Larsen
Messages: 134
Registered: January 2010
Senior Member
On Thursday, 10 May 2012 11:00:49 UTC+2, Konstantinos wrote:
> Dear All,
> Lets supose that i have the folowing matrix lets call it A (14
> columns
> 16 rows) with elements as follows
> 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
> 1 1 1 1 0 0 0 0 0 0 0 0 2 2 2 2
> 1 1 1 1 0 0 0 0 0 0 0 0 2 2 2 2
> 1 1 1 1 0 0 0 0 0 0 0 0 2 2 2 2
> 1 1 1 1 0 0 0 0 0 0 0 0 2 2 2 2
> 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
> 5 5 0 0 7 7 0 0 0 0 0 0 0 0 0 0
> 5 5 0 0 7 7 0 0 0 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0 0 0 0 0 0 3 3 3 3
> 0 0 0 0 0 0 0 0 0 0 0 0 3 3 3 3
> 6 6 0 0 8 8 0 0 0 0 0 0 3 3 3 3
> 6 6 0 0 8 8 0 0 0 0 0 3 3 3 3 3
>
> What i want to do is to make a matrix B (8 columns 8 rows) such as
>
> 1 1 1 1 2 2 2 2
> 1 1 1 1 2 2 2 2
> 1 1 1 1 2 2 2 2
> 1 1 1 1 2 2 2 2
> 5 5 7 7 3 3 3 3
> 5 5 7 7 3 3 3 3
> 5 5 8 8 3 3 3 3
> 5 5 8 8 3 3 3 3
>
> I cant think of anything
> I ll appreciate any help
> Thank u in advance
> Kostas

This looks like some kind of game. You need to specify the rules in order to solve this in general.

PS: I assume one "3" too much in your A matrix, and four of the "5"s in B should really be "6"?

--
Yngvar
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