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Re: diagonal dominant [message #83025 is a reply to message #82949]

Thu, 31 January 2013 05:05

Gompie
Messages: 76
Registered: August 2012

Member

> Can you describe how you are using the SVD to solve your equation? You have mentioned calculating the inverse of A but that is not necessary. From what I've read, it is better to multiply the B vector by the inverse SVD components in succession than calculating the inverse of A and then multiplying B with that

I am now using

svdc,A ,w,u,v,/double
X=SVSOL(U, W, V, rhs,/double), Here A is 255X400 matrix and the duplicate rows have not been removed. Do you think I should do it differently?

> I have no idea what you meant by that. Are you first calculating a solution X to the equation AX=B and then fitting a polynomial to that X? If that polynomial fit is the end result you need, why don't you formulate your model so you can fit the polynomial directly to the measurements in B?

Thats a good idea I can try that !!

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[Message index]

		diagonal dominant By: Gompie on Wed, 30 January 2013 06:26
		Re: diagonal dominant By: Mats Löfdahl on Thu, 31 January 2013 05:26
		Re: diagonal dominant By: Gompie on Thu, 31 January 2013 05:05
		Re: diagonal dominant By: Mats Löfdahl on Thu, 31 January 2013 00:09
		Re: diagonal dominant By: Gompie on Wed, 30 January 2013 22:33
		Re: diagonal dominant By: Mats Löfdahl on Wed, 30 January 2013 15:13
		Re: diagonal dominant By: Gompie on Wed, 30 January 2013 19:36
		Re: diagonal dominant By: Gompie on Wed, 30 January 2013 09:21
		Re: diagonal dominant By: bstecklu on Wed, 30 January 2013 09:06
		Re: diagonal dominant By: Brian Daniel on Wed, 30 January 2013 09:00

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