| Re: bug? or how to distinguish between a Hash and an array of Hashes ? [message #83393 is a reply to message #83392] |
Mon, 04 March 2013 08:11   |
wlandsman
Messages: 743
Registered: June 2000
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Senior Member |
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You could use the TYPENAME function to distinguish the two variables
IDL> print,typename(a)
HASH
IDL> print,typename(c)
OBJREF
although I'm not sure why SIZE(/TNAME) doesn't give the same results. --Wayne
On Monday, March 4, 2013 11:05:03 AM UTC-5, superchromix wrote:
> surprisingly, the ISA function doesn't help here either...
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> pro test
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> a = hash('first', 1, 'second', 2)
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> b = hash('third', 3, 'fourth', 4, 'fifth', 5)
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> print, 'Output of SIZE() for a HASH varible:'
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> print, size(a, /STRUCTURE)
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> c = [a,b]
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> print, 'Output of SIZE() for an array of HASHes:'
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> print, size(c, /STRUCTURE)
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> print, 'Output of ISA(/ARRAY) for scalar hash:'
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> print, isa(a, /array)
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> print, 'Output of ISA(/ARRAY) for array of hashes:'
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> print, isa(c, /array)
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> help, a, output=ahelp
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> help, c, output=chelp
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> print, 'Help for scalar hash:'
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> print, ahelp
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> print, 'Help for array of hashes:'
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> print, chelp
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> end
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> Output of SIZE() for a HASH varible:
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> { OBJREF 11 0 0 2
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> 1 2 0 0 0
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> 0 0 0 0
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> }
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> Output of SIZE() for an array of HASHes:
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> { OBJREF 11 0 0 2
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> 1 2 0 0 0
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> 0 0 0 0
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> }
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> Output of ISA(/ARRAY) for scalar hash:
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> 1
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> Output of ISA(/ARRAY) for array of hashes:
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> 1
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> Help for scalar hash:
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> A HASH <ID=154 NELEMENTS=2>
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> Help for array of hashes:
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> C OBJREF = Array[2]
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