| Re: bug? or how to distinguish between a Hash and an array of Hashes ? [message #83394 is a reply to message #83393] |
Mon, 04 March 2013 08:05   |
markb77
Messages: 217
Registered: July 2006
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Senior Member |
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surprisingly, the ISA function doesn't help here either...
pro test
a = hash('first', 1, 'second', 2)
b = hash('third', 3, 'fourth', 4, 'fifth', 5)
print, 'Output of SIZE() for a HASH varible:'
print, size(a, /STRUCTURE)
c = [a,b]
print, 'Output of SIZE() for an array of HASHes:'
print, size(c, /STRUCTURE)
print, 'Output of ISA(/ARRAY) for scalar hash:'
print, isa(a, /array)
print, 'Output of ISA(/ARRAY) for array of hashes:'
print, isa(c, /array)
help, a, output=ahelp
help, c, output=chelp
print, 'Help for scalar hash:'
print, ahelp
print, 'Help for array of hashes:'
print, chelp
end
Output of SIZE() for a HASH varible:
{ OBJREF 11 0 0 2
1 2 0 0 0
0 0 0 0
}
Output of SIZE() for an array of HASHes:
{ OBJREF 11 0 0 2
1 2 0 0 0
0 0 0 0
}
Output of ISA(/ARRAY) for scalar hash:
1
Output of ISA(/ARRAY) for array of hashes:
1
Help for scalar hash:
A HASH <ID=154 NELEMENTS=2>
Help for array of hashes:
C OBJREF = Array[2]
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