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Re: file I/O and arithmetic calculation [message #84490 is a reply to message #84489]

Thu, 23 May 2013 04:59

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

Keira Wilson writes:

> I would be grateful if someone could guide me:
> I have five text files each of 7 columns by 9 rows
> file_one = 'C:\one.txt'
> file_two = 'C:\two.txt'
> . . .
> file_five = 'C:\five.txt'
>
> How can I calculate the mean of first row for each file, if mean of first column of each file is 50?
> I would appreciate a very simple code to be learn.

What do you imagine the mean of the first column of data has to do with
the mean of the first row of the data? This is kind of like learning
your dentist has three children.

Anyway, something like this would work:

Openr, lun, file_one, /Get_lun
row = Fltarr(7)
ReadF, lun, row
meanRow1 = Mean(row)
Free_Lun, lun

Cheers,

David

--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.idlcoyote.com/
Sepore ma de ni thue. ("Perhaps thou speakest truth.")

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[Message index]

		Re: file I/O and arithmetic calculation By: David Fanning on Thu, 23 May 2013 06:38
		Re: file I/O and arithmetic calculation By: David Fanning on Thu, 23 May 2013 04:59
		Re: file I/O and arithmetic calculation By: Keira Wilson on Thu, 23 May 2013 06:18
		Re: file I/O and arithmetic calculation By: Keira Wilson on Thu, 23 May 2013 07:05

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