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Re: Count duplicate elements in an array but keep their order! [message #85758 is a reply to message #85751]

Tue, 03 September 2013 05:58

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

Josh Sixsmith writes:

> The following might work.
> Using the UNIQ function will give the indices, which you can use to get the value counts.
> To get the counts for each value you'll then need to use the SHIFT function to offset the indices in order subtract from the original indices.

Using the UNIQ function on a floating point array is probably a bad
idea. You might find that ALL your floating point numbers are unique,
depending upon how you arrive at them.

I think to solve this problem you are going to have to convert the
floats to integers of whatever degree of "floating" accuracy makes sense
for the problem. Then work with the integers to find, count, and remove
duplicates.

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.idlcoyote.com/
Sepore ma de ni thue. ("Perhaps thou speakest truth.")

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[Message index]

		Count duplicate elements in an array but keep their order! By: Steve Daal on Fri, 30 August 2013 16:23
		Re: Count duplicate elements in an array but keep their order! By: Josh Sixsmith on Sat, 31 August 2013 08:03
		Re: Count duplicate elements in an array but keep their order! By: David Fanning on Tue, 03 September 2013 05:58
		Re: Count duplicate elements in an array but keep their order! By: Steve Daal on Mon, 16 September 2013 10:51

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