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Re: Solving a non-linear equation [message #88243 is a reply to message #88242]

Wed, 02 April 2014 10:45

Reetsspacey
Messages: 3
Registered: June 2009

Junior Member

On Wednesday, 2 April 2014 11:36:15 UTC-4, Craig Markwardt wrote:
> On Wednesday, April 2, 2014 10:33:43 AM UTC-4, Reetsspacey wrote:
>
>> Hi,
>
>>
>
>>
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>>
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>> My problem is this: I have a non-linear equation, of the form y = exp(x)+x. I have a large matrix of Y values, and for each cell (Y-value) I would like to calculate a best-fit X. How can I do this???
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>
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> The easiest way is to use Newton's method.
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> If you're trying to find the root of f(x), given a trial solution of x0, the next best solution is,
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> x = x0 - f(x0) / f'(x0)
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> where f'(x0) is the derivative of the function. Now you have a new x0 and can try again for multiple iterations.
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> For you, this would be, in IDL language,
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> for i = 0, n_iter-1 do begin
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> x = x0 - (x + exp(x) - y)/(1 + exp(x))
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> x0 = x
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> endfor
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> Your function is very well behaved (no extrema) so you should be able to pick x0=0 as your starting point and then keep iterating until you achieve the desired precision.
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> Craig

Brilliant, that makes sense! Thank you!

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[Message index]

		Solving a non-linear equation By: Reetsspacey on Wed, 02 April 2014 07:33
		Re: Solving a non-linear equation By: Craig Markwardt on Wed, 02 April 2014 08:36
		Re: Solving a non-linear equation By: Reetsspacey on Wed, 02 April 2014 10:45

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