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Re: how can you convert CMIP5 model output time ? [message #89087 is a reply to message #89086]

Wed, 23 July 2014 13:45

Michael Galloy
Messages: 1114
Registered: April 2006

Senior Member

On 7/23/14, 1:59 PM, siumtesfai@gmail.com wrote:
> how can you convert CMIP5 model output time to the Julian day?

It looks like CMIP5 model output time is specified in days since some
basetime, bt, specified by the user (looks like it is given in the
"units" attribute to the variable), so something like:

jday = output_day + julday(bt_year, bt_month, bt_day, ...)

should do it.

Mike
--
Michael Galloy
www.michaelgalloy.com
Modern IDL: A Guide to IDL Programming (http://modernidl.idldev.com)
Research Mathematician
Tech-X Corporation

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[Message index]

		how can you convert CMIP5 model output time ? By: siumtesfai on Wed, 23 July 2014 12:59
		Re: how can you convert CMIP5 model output time ? By: Michael Galloy on Wed, 23 July 2014 13:45
		Re: how can you convert CMIP5 model output time ? By: siumtesfai on Wed, 23 July 2014 14:00
		Re: how can you convert CMIP5 model output time ? By: siumtesfai on Wed, 23 July 2014 17:37
		Re: how can you convert CMIP5 model output time ? By: Fabzi on Thu, 24 July 2014 01:44
		Re: how can you convert CMIP5 model output time ? By: siumtesfai on Thu, 24 July 2014 17:00
		Re: how can you convert CMIP5 model output time ? By: Fabzi on Fri, 25 July 2014 01:51

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