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Re: Locating desired values in an array. [message #89094 is a reply to message #89093]

Wed, 23 July 2014 23:26

Moritz Fischer
Messages: 32
Registered: June 2013

Member

Unless you know more about the nature of those track numbers I'd loop
over them. You can get the track numbers using UNIQ() and then do
something like this:

tn = uniq( yourarray[1,*] )
value = fltarr( n_elements( tn ) )

for i=0,n_elements(tn)-1 do begin

subset = WHERE( yourarray[1,*] EQ tn[i] )

void = min(abs( yourarray[0,subset] + 42. ), min_index )

value[i] = yourarr[0, subset[min_index] ]

end

Am 24.07.2014 03:50, schrieb gpeterso@ucsc.edu:
> So i have an array that is [2,58]. I need the number that is closet
> to -42 for each time the track number increases by one. So for
> example for track number 28742 I should get the third bin number of
> -42.6996. I am very confused on how to do approach this.
>
>
>

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[Message index]

		Locating desired values in an array. By: gpeterso on Wed, 23 July 2014 18:50
		Re: Locating desired values in an array. By: Moritz Fischer on Wed, 23 July 2014 23:26
		Re: Locating desired values in an array. By: gpeterso%ucsc.edu on Thu, 24 July 2014 11:19
		Re: Locating desired values in an array. By: Moritz Fischer on Fri, 25 July 2014 01:16
		Re: Locating desired values in an array. By: Matthew Argall on Thu, 24 July 2014 05:13

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