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Re: Locating desired values in an array. [message #89098 is a reply to message #89093]

Thu, 24 July 2014 05:13

Matthew Argall
Messages: 286
Registered: October 2011

Senior Member

Here is a solution using Histogram and reverse indices.

;Create data
tn = [replicate(3, 5), replicate(2, 3), replicate(9, 8)]
lat = 42 + randomu(5, n_elements(tn))

;Histogram to find repeated track numbers
hist = histogram(tn, MIN=0, REVERSE_INDICES=ri)

;Allocate memory to result.
nHist = n_elements(hist)
theNumber = fltarr(nHist)
theIndex = intarr(nHist) - 1

;Loop through each bin
for i = 0, nHist-1 do begin
;Only analyze bins with something in them
if ri[i+1] gt ri[i] then begin
;Find the closest number and its index
theNumber[i] = min( abs( 42 - abs(lat[ri[ri[i]:ri[i+1]-1]]) ), iMax )
theIndex[i] = ri[i] + iMax
endif
endfor

;Weed out empty histogram bins
iKeep = where(theIndex ne -1)
theNumber = theNumber[iKeep]
theIndex = theIndex[iKeep]

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[Message index]

		Locating desired values in an array. By: gpeterso on Wed, 23 July 2014 18:50
		Re: Locating desired values in an array. By: Moritz Fischer on Wed, 23 July 2014 23:26
		Re: Locating desired values in an array. By: gpeterso%ucsc.edu on Thu, 24 July 2014 11:19
		Re: Locating desired values in an array. By: Moritz Fischer on Fri, 25 July 2014 01:16
		Re: Locating desired values in an array. By: Matthew Argall on Thu, 24 July 2014 05:13

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