| Re: debugging with new variables (dictionary, hash, ...) [message #90020 is a reply to message #90010] |
Thu, 15 January 2015 05:27   |
wlandsman
Messages: 743
Registered: June 2000
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Senior Member |
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On Wednesday, January 14, 2015 at 5:28:50 PM UTC-5, Helder wrote:
> If you type .SO first, then it will (obviously) step over the line "print, retValue(...)". If you use F5 to step in (don't know what the command line option is), then you can't get out with .SO. With .OUT you go too far out!
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> Thanks anyway,
> Helder
I don't understand this comment. .SO will *not* step over the line "print, retValue(...)". Stepover is perhaps an unfortunate name. It does not skip or "step over" any lines. It takes one step and *if* you enter another procedure in that step it continues until you return (e.g exit the HASH call). This appears to be exactly what you are asking for.
As for .OUT you would use it once you step into the HASH routine to get out of the HASH routine in one keystroke. Of course, by using .SO you can avoid ever entering the hash routine in the first place.
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