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Re: Gradient idl [message #90577 is a reply to message #90561]

Wed, 11 March 2015 08:41

Jeremy Bailin
Messages: 618
Registered: April 2008

Senior Member

> I am interested in the magnitude of the gradient
>
> Result_xy=sqrt(result_x^2 +result_y^2)
> right ?

Yes.

> I looked at the following function but it does not handle missing data

Yes, that code is effectively doing the same thing. It's probably faster because SHIFT is fast compared to CONVOL. But it's definitely easier to get CONVOL to deal with missing data, so in your case I think it would be better.

-Jeremy.

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[Message index]

		Gradient idl By: siumtesfai on Mon, 09 March 2015 22:12
		Re: Gradient idl By: siumtesfai on Tue, 10 March 2015 09:00
		Re: Gradient idl By: Jeremy Bailin on Tue, 10 March 2015 09:13
		Re: Gradient idl By: siumtesfai on Tue, 10 March 2015 09:39
		Re: Gradient idl By: Jeremy Bailin on Wed, 11 March 2015 08:41
		Re: Gradient idl By: siumtesfai on Wed, 26 August 2015 09:02

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