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Re: 8 byte to double? [message #92600 is a reply to message #92599]

Wed, 20 January 2016 04:58

Lajos Foldy
Messages: 176
Registered: December 2011

Senior Member

On Wednesday, January 20, 2016 at 1:39:07 PM UTC+1, LNpellen wrote:
> I'm lost - and I thought I had solved this previously, but I simply can't find it (maybe it was in php or something...).
>
> Some values in the DICOM header for some vendors happens to save floating (double-presition?) values as 8-bytearrays
>
> Is there a simple way in IDL to convert this bytearray to a double without coding the type conversion yourself?
>
> I couldn't manage to use the DOUBLE function for this.
>
> Ex.:
> I have the byte array [205 204 204 204 204 204 49 64] and it think from my annoyingly short notes that it should be 17.8...?
>
> Best regards,
> Ellen

IDL> b=[205b,204b,204b,204b,204b,204b,49b,64b]
IDL> print, fix(b, 0, 1, type=5)
17.800000

regards,
Lajos

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[Message index]

		8 byte to double? By: LNpellen on Wed, 20 January 2016 04:39
		Re: 8 byte to double? By: Lajos Foldy on Wed, 20 January 2016 04:58
		Re: 8 byte to double? By: David Fanning on Wed, 20 January 2016 05:34
		Re: 8 byte to double? By: LNpellen on Wed, 20 January 2016 05:45

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