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Re: adding a 4th dimension to 3D array during concatenation [message #92878 is a reply to message #92869]

Wed, 16 March 2016 20:46

wlandsman
Messages: 743
Registered: June 2000

Senior Member

On Tuesday, March 15, 2016 at 6:37:18 PM UTC-4, Wayana Dolan wrote:
You can go ahead with the list suggestions but if you do know how many arrays you want to concatenate, then it is even more efficient to build your array beforehand.

outarr = fltarr(91,41,33,16)
for i=0,15 do begin
.... Make an array x with dimensions (91,41,33)
outarr[0,0,0,i] = x
endfor

x = transpose(x, [3,0,1,2])

Now for efficiency reasons it is better to make the last dimension 16 rather than the first. But if you really want the first dimension to be the "counting" dimension then you can use TRANSPOSE() as above to rearrange things.

> So outside a loop I start out with an empty array (ex. array=[ ] ). Then each time through the loop, I make an array with 3 dimensions (for example, array x has dimensions[91, 41, 33] ), and then concatinate it to the previous array. (ex. array=[array, x]).
>
> Lets say we run through the loop 16 times. What I'd like as a result is something that has dimensions like this [16, 91, 41, 33].
>
> I'm not sure how to do this... I've looked at IDL coyote's concatenation tutorial, and still am having trouble.
>
> I'm pretty new to coding period, so this is a challenge. Any ideas?

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[Message index]

		adding a 4th dimension to 3D array during concatenation By: wdolan on Tue, 15 March 2016 15:37
		Re: adding a 4th dimension to 3D array during concatenation By: Paul Van Delst[1] on Wed, 16 March 2016 08:00
		Re: adding a 4th dimension to 3D array during concatenation By: Jim Pendleton on Wed, 16 March 2016 18:46
		Re: adding a 4th dimension to 3D array during concatenation By: wlandsman on Wed, 16 March 2016 20:46
		Re: adding a 4th dimension to 3D array during concatenation By: Guilherme Gualda on Wed, 16 March 2016 22:52

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